Answer
B
Work Step by Step
$HS^-/H_2S$ is equally strong as an acid or as a base $K_a=K_b=10^{-7}$, $H_3PO_4/H_2PO_4^-$ is much stronger as an acid than as a base, so the equilibrium is predominantly to the right.
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 16 Principles of Chemical Reactivity: The Chemistry of Acids and Bases - 16-5 Predicting the Direction of Acid-Base Reactions - Review & Check for Section 16-5 - Page 603: 2
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