Answer
D
Work Step by Step
$[OH^-]=10^{-(14-pH)}$
$[OH^-]=2.88\times10^{-4}\ M$
$Sr(OH)_2=Sr^{2+}+2\ OH^-$
$[Sr(OH_2)]_0=1/2\ [OH^-]=1.44\times10^{-4}\ M$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 16 Principles of Chemical Reactivity: The Chemistry of Acids and Bases - 16-2 Water and the pH Scale - Review & Check for Section 16-2 - Page 592: 3
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