Answer
$p(CO)=0.001\ atm$
Work Step by Step
$K_c=[HbCO][O_2]/[HbO_2][CO]$
Fatality: $[HbCO]/[HbO_2]\approx1$
$K_{c,fatal}=[O_2]/[CO]\approx K_{p,fatal}$
$200=0.20/p(CO)$
$p(CO)=0.001\ atm$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 15 Principles of Chemical Reactivity: Equilibria - Study Questions - Page 583f: 57
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