Answer
See the answer below.
Work Step by Step
$P=p(NO_2)+p(N_2O_4)\rightarrow, p(NO_2)=x, p(N_2O_4)=0.15-x$
$K_p=p(N_2O_4)/p(NO_2)^2$
$7.1=0.15-x/x^2$
$7.1x^2+x-0.15=0$
$x=0.091$
$p(NO_2)=0.091\ atm, p(N_2O_4)=0.059\ atm$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 15 Principles of Chemical Reactivity: Equilibria - Study Questions - Page 583e: 50
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