Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 15 Principles of Chemical Reactivity: Equilibria - Study Questions - Page 583d: 34

Answer

$0.0273\ M$

Work Step by Step

$K=[CH_4][CCl_4]/[CH_2Cl_2]^2$ $1.05=0.0163x/0.0206^2$ $x=0.0273\ M$
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