Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 15 Principles of Chemical Reactivity: Equilibria - Study Questions - Page 583c: 24

Answer

$2.39$

Work Step by Step

$K=[H_2]/[H_2O]$ $K_1=[H_2][CO_2]/[H_2O][CO]$ $K_2=[CO_2]/[CO]$ $\frac {K_1}{K_2}=\dfrac{[H_2][CO_2]}{[H_2O][CO]}\dfrac{[CO]}{[CO_2]}=K$ $K=1.6/0.67=2.39$
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