Answer
See the answer below.
Work Step by Step
a) The concentrations of CO and H2O are $0.11\ mol\div 50.0\ L=0.0022\ M$, and of H2 and CO2 are $0.087\ mol\div 50.0\ L=0.00174\ M$.
The equilibrium constant is given by:
$K=[CO][H_2O]/[CO_2][H_2]$
$K=0.0022\times0.0022/0.0017/0.0017=1.60$
b) Number of moles reacted of CO2 and H2 each: x
Number of moles of H2O and CO formed: x
$K=[CO][H_2O]/[CO_2][H_2]$
$K=(x/V).(x/V)/[(0.010-x)/V(0.010-x)/V]$
$1.60=x^2/(0.010-x)^2$
$1.265\times(0.010-x)=x$
$x=0.0056$
0.0056 mol of each
