Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 15 Principles of Chemical Reactivity: Equilibria - Study Questions - Page 583a: 7

Answer

$K=1.207$

Work Step by Step

The equilibrium constant is: $K=[PCl_3][Cl_2]/[PCl_5]$ $K=1.3\times10^{-2}\ M\times3.9\times10^{-3}\ M/4.2\times10^{-5}\ M$ $K=1.207$
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