Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 15 Principles of Chemical Reactivity: Equilibria - 15-6 Disturbing a Chemical Equilibrium - Review & Check for Section 15-6 - Page 581: 2

Answer

A

Work Step by Step

Since $[X]=n_X/V$, increasing the volume decreases the concentration of all species by the same factor, let's call it f > 1. $Q=([NH_3]_0/f)^2/([N_2]_0/f)([H_2]_0/f)^3=f^4/f^2\times[NH_3]_0/[N_2]_0[NH_3]_0=K.f^2$ Since Q>K, the equilibrium shifts to the left.
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