Answer
C
Work Step by Step
$K_1=[HBr]^2/[H_2][Br_2]$
$K_2=[H]^2/[H_2]$
$K_3=[Br]^2/[Br_2]$
$\sqrt{K_1/(K_2.K_3)}=[HBr]/[H][Br]=K\rightarrow K=2.74\times10^{33}$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 15 Principles of Chemical Reactivity: Equilibria - 15-5 More about Balanced Equations and Equilibrium Constants - Review & Check for Section 15-5 - Page 574: 1
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