Answer
B
Work Step by Step
The concentration of reacted N2O4
$0.010/2-0.0042=0.0008\ M$
By stoichiometry:
$[NO_2]=2\times reacted=0.0016\ M$
$K=[NO_2]^2/[N_2O_4]$
$K=0.0016^2/0.0042$
$K=6.09\times10^{-4}$
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