Answer
See the answer below.
Work Step by Step
a) At constant [CO], doubling [NO2] doubles the initial rate: first-order with respect to CO.
At constant [NO2], doubling [CO] doubles the initial rate: first-order with respect to NO2.
b) $r=k[CO][NO_2]$
c) In the first line of the table:
$3.4\dot{}10^{-8}\ mol/L.h=k\dot{}5.1\dot{}10^{-4}\ mol/L\dot{}0.35\dot{}10^{-4}\ mol/L$
$k=1.905\ L/mol.h$
