Answer
$3.1\%$
Work Step by Step
For a first-order reaction:
$ln(C/C_0)=-kt;k=0.693/t_{1/2}$
$ln(f)=-0.693\times(t/t_{1/2})\rightarrow ln(f)=-0.693\times 5$
$f=0.031\ or\ 3.1\%$
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