Answer
0.14 mg in water and 4.86 mg in CCl4
Work Step by Step
Solubility in water: $S_w=m_w/25.0\ mL$
Solubility in CCl4 $S_{CCl4}=85S_w=m_{CCl4}/10.0\ mL=(5.0\ mg-m_w)/10.0\ mL$
$85(m_w/25)=(5-m_w)/10\rightarrow m_w=0.143\ mg\rightarrow m_{CCl4}=4.857\ mg$
0.14 mg in water and 4.86 mg in CCl4
