Answer
$106.34^{\circ}C$
Work Step by Step
Number of moles:
$39.1\ g\div 58.44\ g/mol=0.669\ mol$
Molality:
$0.669\ mol \div 0.1\ kg=6.69\ m$
Boiling point elevation:
$\Delta T_b = iK_bm=1.85\times0.5121^{\circ}C/m\times 6.69\ m=6.34^{\circ}C$
Boiling point: $100+6.34=106.34^{\circ}C$