Answer
See the answer below.
Work Step by Step
In 1 kg of the solution:
Number of moles of solute: $950\ g\div 98.08\ g/mol=9.69\ mol$
Molality: $9.69\ mol\div 0.05\ kg=193.72\ m$
Volume of solution: $1000\ g\div 1.84\ g/cm^3=543.47\ cm^3=0.54\ L$
Molarity: $9.69\ mol\div 0.54\ L=17.83\ M$
