Answer
C
Work Step by Step
From the definition of freezing point depression:
$\Delta T_{fp}=K_{fp}m$
$-0.762^{\circ}C=-1.86^{\circ}C/m\times m_s$
$m_s=0.41\ molal$
$m_s=(2.50\ g\div M_s)/0.05\ kg$
$M_s=121.95\ g/mol$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 13 Solutions and Their Behavior - 13-4 Colligative Properties - Review & Check for Section 13-4 - Page 497: 4
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