Answer
$855\ nm$
Work Step by Step
$\hat E=E/N_A=h.\nu=h.c/\lambda$
$h.c.N_A=0.120\ J.m/mol$
$\lambda=0.120\div 140000=8.55\times10^{-7}\ m=855\ nm$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 12 The Solid State - Study Questions - Page 467e: 51
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