Answer
$N_A=6.0226\times10^{23}$
Work Step by Step
Volume: $(5.46295\times10^{-8}\ cm)^3=1.6304\times10^{-22}\ cm^3$
Mass: $3.1805\ g/cm^3\times 1.6304\times10^{-22}\ cm^3=5.185\times10^{-22}\ g$
$5.185\times10^{-22}\ g=(4\times40.078+8\times18.998)\ g/mol\div N_A$
$N_A=6.0226\times10^{23}$