Answer
A
Work Step by Step
$ln\dfrac{P_2}{P_1}=-\dfrac{\Delta H_v}{R}×\left(\dfrac 1{T_2}-\dfrac 1{T_1}\right)$
$-8.314×ln 0.1067= \Delta H_v×(0.000641)$
$\Delta H_v=29.0\ kJ/mol$
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