Answer
See the answer below.
Work Step by Step
Number of moles:
$n=(209/760×1\ atm)×0.732\ L/0.082/294=0.00835\ mol$
Molecular weight:
$0.37\ g\div 0.00835\ mol=44.3\ g/mol$
Which is closer to $CO_2$'s molecular weight.
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 10 Gases and Their Properties - Study Questions - Page 403f: 79
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