Answer
See the answer below.
Work Step by Step
Number of moles of silicon:
$2.25\ g\div 28.085\ g/mol=0.08\ mol$
Number of moles of $CH_3Cl$
$n=PV/RT$
$n=0.206\ mol$
Since this is greater than $2×0.08\ mol$, $CH_3Cl$ is in excess.
Mass produced:
$0.08\ mol×129.06\ g/mol=10.34\ g$
Partial pressure at the final temperature:
$P_x=n_xRT/V$
$P_x=0.08\ mol×0.082057\ L.atm/mol.K×368\ K\div 6.56\ L$
$P_x=0.0369\ atm$
