Answer
270. mm Hg
Work Step by Step
$V_{1}$ = 500 L
$P_{1}$ = 67.5 mm Hg
$V_{2}$ = 125 mL
According to Boyle's law, $P_{1}V_{1} = P_{2}V_{2}$
Or $P_{2}$ = $\frac{P_{1}V_{1}}{V_{2}}$ = $\frac{67.5 mm Hg\times500. mL}{125 mL}$ = 270. mm Hg
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 10 Gases and Their Properties - Study Questions - Page 403a: 5
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
