Answer
These masses are consistent with the law of multiple proportions.
Work Step by Step
Ratio of mass of sulphur per gram palladium in the compound A to compound B = $\frac{0.603}{0.301} = 2$
Ratio of mass of sulphur per gram palladium in the compound B to compound C = $\frac{0.301}{0.151} = 2$
Ratio of mass of sulphur per gram palladium in the compound A to compound C = $\frac{0.603}{0.151} = 4$
The ratio of these masses are small whole numbers.
Hence, these masses are consistent with the law of multiple proportions.