Answer
63.67 g/mol
Work Step by Step
7.36g Cu + 0.51g Zn = 7.87g sample
($\frac{7.36g Cu}{7.87g sample}$)($\frac{63.55 g Cu}{mol Cu}$) + ($\frac{0.51g Zn}{7.87g sample}$)($\frac{65.41 g Zn}{mol Zn}$) = 63.67 g/mol
Chemistry: A Molecular Approach (3rd Edition)
by Tro, Nivaldo J.
Published by
Prentice Hall
ISBN 10:
0321809246
ISBN 13:
978-0-32180-924-7
Chapter 2 - Sections 2.1-2.9 - Exercises - Challenge Problems - Page 84: 127
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