Answer
$^{4}_{2}He$ and $^{4}_{2}He$.
Work Step by Step
From the given information, nuclear equation can be written as
$^{6}_{3}Li+\,^{2}_{1}H\rightarrow \,^{A}_{Z}X+ \,^{A}_{Z}X$ where $X$ is the symbol of the particle, $A$ is the mass number and $Z$ is the charge.
Since sum of the charges and masses should be equal on both the sides, we have
$2A=8$ and $2Z=4$
$\implies A=4$ and $Z=2$
The symbol of particle with $Z=2$ is $He$.
Therefore the identical particles are
$^{4}_{2}He$ and $^{4}_{2}He$.
