Answer
KBr breaks apart to K$^+$ and Br$^-$.
K$^+$ (l) + e$^-$ --> K(l) and 2Br$^-$(l) --> Br$_{2}$(g) + 2e$^-$
Work Step by Step
KBr breaks apart to K$^+$ and Br$^-$.
K$^+$ (l) + e$^-$ --> K(l) and 2Br$^-$(l) --> Br$_{2}$(g) + 2e$^-$
Chemistry: A Molecular Approach (3rd Edition)
by Tro, Nivaldo J.
Published by
Prentice Hall
ISBN 10:
0321809246
ISBN 13:
978-0-32180-924-7
Chapter 18 - Sections 18.1-18.9 - Exercises - Problems by Topic - Page 907: 91
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