Answer
$4Ag(s) + 8CN^{-}(aq) + O_{2}(g) + 2H_{2}O(l) → 4Ag(CN)_{2}^{-}(aq) + 4OH^{-}(aq)$
Work Step by Step
Since the reaction is in basic medium, we add water to the left hand side and OH- to the right hand side of the equation
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