Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 16 - Sections 16.1-16.8 - Exercises - Problems by Topic - Page 808: 100a

Answer

$Hg_2Br_2$ isn't more soluble in acidic solution than in pure water, because there are no significant bases in the ionic compound.

Work Step by Step

1. Identify the acidity/basicity of each ion in the compound: - $Hg^{2+}$: No significant acidity/basicity; - $Br^{-}$: No significant acidity/basicity. (It is the conjugate pair of a Strong acid ($HBr$)) - Since we don't have any significant acid/base, the acidity of the solution will not affect the solubility of the compound.
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