Answer
The initial pH is equal to 13.06
Work Step by Step
- The only significant non-neutral compound in the solution is $RbOH$, which is a strong base, so:
$[OH^-] = [RbOH]_{initial} = 0.115M$
1. Calculate the pOH:
$pOH = -log[OH^-]$
$pOH = -log( 0.115)$
$pOH = 0.94$
2. Find the pH:
$pH + pOH = 14$
$pH + 0.9393 = 14$
$pH = 13.06$
