Answer
$2H_2O(l) \lt -- \gt H_3O^+(aq) + OH^-(aq)$
$K_w = [H_3O^+][OH^-]$
The $K_w$ value at $25^{\circ}C$ is $1.0 \times 10^{-14}$
Work Step by Step
This is called the autoionization of water, because the only reactant is $H_2O$.
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