Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 15 - Sections 15.1-15.12 - Exercises - Cumulative Problems - Page 749: 128c

Answer

The pictured base ($HC{O_3}^-$) is weak.

Work Step by Step

What happened there: This was a sodium bicarbonate ($NaHCO_3$) solution, this salt completely dissociated in water, producing the pH-neutral ion: $Na^+$, and the weak base: $H{CO_3}^-$; Since we can identify $HC{O_3}^-$ (base) molecules in the solution, the base didn't ionizate $100\%$ into $OH^-$ and $H_2CO_3$ ions, making this a weak base.
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