Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 15 - Sections 15.1-15.12 - Exercises - Conceptual Problems - Page 751: 158b

Answer

$0.0100M$ $KClO_2$ is more basic.

Work Step by Step

1. Identify each conjugate pair of the ions in the solutions. First solution: $K^+$: $KOH$: Strong base. $Cl^-$: $HCl$: Strong acid. Second solution: $K^+$: $KOH$: Strong base. $Cl{O_2}^-$: $HClO_2$: Weak acid. 2. Therefore: First solution: Neutral Second solution: Basic. So, the second solution is more basic.
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