Answer
160 mL=.16 L
Work Step by Step
Mass of $BaCl_{2}$ = 15.0 g
Molar mass of $BaCl_{2}$ = 208.23 g/mol
Molarity = 0.45 M = 0.45 mol/L
Volume of solution in L = $\frac{Mass\div Molar.mass}{Molarity}$ = $\frac{15.0g\div208.23gmol^{-1}}{0.45molL^{-1}}$ = 0.16 L = 160 mL