Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 16 - Applications of Aqueous Equilibria - Section Problems - Page 710: 74

Answer

$pH = 4.04$

Work Step by Step

1. Calculate the pKa Value $pKa = -log(Ka)$ $pKa = -log( 1.8 \times 10^{- 4})$ $pKa = 3.74$ 2. Using the Henderson–Hasselbalch equation: $pH = pKa + log(\frac{[Base]}{[Acid]})$ $pH = 3.74 + log(\frac{0.5}{0.25})$ $pH = 3.74 + log(2)$ $pH = 3.74 + 0.301$ $pH = 4.04$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.