Answer
$[OH^-] = 7.143 \times 10^{- 11}M$
The solution is acidic.
Work Step by Step
$[H_3O^+] * [OH^-] = Kw = 10^{-14}$
$ 1.4 \times 10^{- 4} * [OH^-] = 10^{-14}$
$[OH^-] = \frac{10^{-14}}{ 1.4 \times 10^{- 4}}$
$[OH^-] = 7.143 \times 10^{- 11}M$
Since: $[H_3O^+] > [OH^-]$, the solution is acidic.