Answer
$[H_3O^+] = 5 \times 10^{- 9}M$
It is a basic solution.
Work Step by Step
$[OH^-] * [H_3O^+] = Kw = 10^{-14}$
$ 2 \times 10^{- 6} * [H_3O^+] = 10^{-14}$
$[H_3O^+] = \frac{10^{-14}}{ 2 \times 10^{- 6}}$
$[H_3O^+] = 5 \times 10^{- 9}$
- Since $[OH^-] > [H_3O^+]$, the solution is basic.
