Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 1 - Chemical Tools: Experimentation and Measurement - Worked Example - Page 14: 6

Answer

The identity of the metal in the bracelet is 100% silver.

Work Step by Step

1. First we must find the volume of the bracelet. This is done by subtracting the starting 10.0 mL from the final 17.61 mL. 17.61 mL - 10.0 mL = 7.61 mL 2. Then, we must make the conversion from $\frac{g}{mL}$ to $\frac{g}{cm^{3}}$. Note, 1 mL = 1 $cm^{3}$. ($\frac{80.0 g}{7.61 mL}$)($\frac{1 mL}{1 cm^{3}}$) = 10.5 $\frac{g}{cm^{3}}$ Note, we are keeping with the 3 significant figures stated in the problem.
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