Answer
$1.0\,g/cm^{3}$
Work Step by Step
Using conversion factors, we have
Density= $0.037\,\frac{lbs}{in^{3}}\times\frac{453.592\,g}{1\,lbs}\times\frac{1\,in^{3}}{16.387\,cm^{3}}$
$=1.0\,g/cm^{3}$
Chemistry (7th Edition)
by McMurry, John E.; Fay, Robert C.; Robinson, Jill Kirsten
Published by
Pearson
ISBN 10:
0321943171
ISBN 13:
978-0-32194-317-0
Chapter 1 - Chemical Tools: Experimentation and Measurement - Chapter Problems - Page 32: 108
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