Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 8 - Periodic Relationships Among the Elements - Questions & Problems - Page 361: 8.26

Answer

The metal is Iron [Fe].

Work Step by Step

Let the metal ion be $M^{+3}$; it contain 5 electrons in the 3d shell. The electronic configuration of $M^{+3}$ is $1s^{2} 2s^{2}2p^{6} 3s^{2}3p^{6}3d^{5}$. If there are 3d orbitals, the valence shell will be 4s. It’s parent metal is the one with 3 more electrons, and it is added in 4s and 3d orbital as the electrons are removed from the valence shell and then from the penultimate shell. Therefore, electronic configuration of M is $1s^{2} 2s^{2}2p^{6} 3s^{2}3p^{6}4s^{2}3d^{6}$ or $[Ar] 4s^{2}3d^{6}$. The atomic number of the element is 26, and the metal is iron [Fe].
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