Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 7 - Quantum Theory and the Electronic Structure of Atoms - Questions & Problems - Page 316: 7.19

Answer

$1.29\times10^{-15}\,J$

Work Step by Step

Energy $E=\frac{hc}{\lambda}$ where $h$ is the Planck's constant, $c$ is the speed of light and $\lambda$ is the wavelength. $\implies E=\frac{(6.626\times10^{-34}\,J\cdot s)(3.00\times10^{8}\,m/s)}{0.154\times10^{-9}\,m}$ $=1.29\times10^{-15}\,J$
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