Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0132525763
ISBN 13: 978-0-13252-576-3

Chapter 4 - Atomic Structure - 4 Assessment - Page 122: 53

Answer

6.941 amu

Work Step by Step

We multiply the mass of the isotope and its relative abundance (shown as a decimal). And then we add the products together. Isotope 1: mass= 6.015 amu (7.5%) Isotope 2: mass= 7.016 amu (92.5%) = 6.015 (7.5%) + 7.016 (92.5%) = 6.015 (0.075%) + 7.016 (0.925%) = 6.941 amu
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