Answer
a) $^{3}_{1}H$ -> $^{3}_{2}He + ^{0}_{-1}e$
b) $^{28}_{12}Mg$ -> $^{28}_{13}Al + ^{0}_{-1}e$
c) $^{131}_{53}I$ -> $^{131}_{54}Xe + ^{0}_{-1}e$
d) $^{75}_{34}Se$ -> $^{75}_{35}Br + ^{0}_{-1}e$
Work Step by Step
a) $^{3}_{1}H$ -> $^{3}_{2}He + ^{0}_{-1}e$
b) $^{28}_{12}Mg$ -> $^{28}_{13}Al + ^{0}_{-1}e$
c) $^{131}_{53}I$ -> $^{131}_{54}Xe + ^{0}_{-1}e$
d) $^{75}_{34}Se$ -> $^{75}_{35}Br + ^{0}_{-1}e$
