Answer
a) The part which is missing from the nuclear reaction is $\frac{1}{1}H$
b)The part which is missing from this nuclear reaction is $\frac{81}{210}Ti$
c) The part which is missing from this nuclear reaction is $\frac{15}{27}P$
d) $\frac{66}{29}Cu$--$\gt$$\frac{66}{30}Zn$ +$\frac{0}{-1}e$
Work Step by Step
a) When you look at the periodic table, it is important to remember that the atomic number is written as the subscript and the mass number is written as the superscripts. It also must be conserved in the reactants and products.
b) Remember that the atomic number is written as the subscript and the mass number is written as the superscripts. To get this answer you would need to subtract the atomic and mass number to find the unknown element.
c) Remember that the atomic number is written as the subscript and the mass number is written as the superscripts. Here you will subtract the mass and the atomic number of the products from the reactants.
d) To calculate the answer, you need to look at the subscript of the element which has the atomic number and the superscripts which has the mass number. It is important to remember that the number of particles must be equal on both sides of the arrow. Now you have to do the math. On one side of the arrow is 29 as the atomic number but on the other side is 30 as the atomic number. If you add a -1 to the right of the arrow then 30+ -1= 29 and now you have 29 as the atomic number on each side.
