Answer
Rb + I2 -> RbI2
See explanation.
See explanation.
Work Step by Step
The oxidizing agent is I.
The oxidation number of I INCREASES from 0 to +2.
Barium undergoes a single displacement in which the hydrogen is displaced from water.
H is reduced. It is the oxidizing agent.
H oxidation number decreases from 1+ to 0.
To predict the product of the reaction, observe that the reaction follows the format of a single replacement reaction, in which the Al replaces Iron, a less active metal in iron (II) sulfate.
To predict the product of the reaction, observe that the reaction follows the format of a single replacement reaction, in which the Al replaces Iron, a less active metal in iron (II) sulfate.
Iron's oxidation number is reduced from 2+ to 0 in the reaction - meaning it "gains the electrons" the oxidized atom loses - it is the oxidizing agent.