Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0132525763
ISBN 13: 978-0-13252-576-3

Chapter 20 - Oxidation-Reduction Reactions - 20 Assessment - Page 721: 54

Answer

16H+ + 2Cr2O7 2- + C2H5OH --> 4Cr3+ + 2CO2 +11H2O This is a Oxidizing agent.

Work Step by Step

16H+ + 2Cr2O7 2- + C2H5OH --> 4Cr3+ + 2CO2 +11H2O This is a Oxidizing agent.
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