Answer
$K_w=K_aK_b$
$\frac{[H^+][A^-]}{HA}\times\frac{[HA][OH^-]}{A^-}=[H^+][OH^-]$
Work Step by Step
$K_w=K_aK_b$
$\frac{[H^+][A^-]}{HA}\times\frac{[HA][OH^-]}{A^-}=[H^+][OH^-]$
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