Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0132525763
ISBN 13: 978-0-13252-576-3

Chapter 19 - Acids, Bases, and Salts - 19 Assessment - Page 687: 110

Answer

$K_w=K_aK_b$ $\frac{[H^+][A^-]}{HA}\times\frac{[HA][OH^-]}{A^-}=[H^+][OH^-]$

Work Step by Step

$K_w=K_aK_b$ $\frac{[H^+][A^-]}{HA}\times\frac{[HA][OH^-]}{A^-}=[H^+][OH^-]$
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