Answer
$(HPO_4)^{2-}$ -> $H^+ + (PO^4)^{3-}$
$(HPO_4)^{2-}+H^+$ -> $(H_2PO^4)^{-}$
Work Step by Step
$(HPO_4)^{2-}$ -> $H^+ + (PO^4)^{3-}$
$(HPO_4)^{2-}+H^+$ -> $(H_2PO^4)^{-}$
Chemistry (12th Edition)
by Wilbraham
Published by
Prentice Hall
ISBN 10:
0132525763
ISBN 13:
978-0-13252-576-3
Chapter 19 - Acids, Bases, and Salts - 19 Assessment - Page 685: 81
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