Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0132525763
ISBN 13: 978-0-13252-576-3

Chapter 16 - Solutions - 16 Assessment - Page 549: 78

Answer

Assuming density = 1 g/mL M = 0.114 / 0.1 L = 1.14

Work Step by Step

Moles of NaHCO3= 84g Divide 9.6 by 84, which equals .114. Then take .144 divided by 5.67. This will then give you .0201. This is your first answer. To find the molality, you'd take .114 divided by .1. This would then give you 1.14
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