Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0132525763
ISBN 13: 978-0-13252-576-3

Chapter 16 - Solutions - 16 Assessment - Page 548: 60

Answer

A) 0.50 moles NaCl, 29.25g NaCl B) 1 mole KNO3, 110 g KNO3 C) 0.025 moles of CaCl2, 2.75g CaCl2 D) 0.6 moles od Na2SO4, 85.2g Na2SO4

Work Step by Step

Knowing the formula for molarity as moles of solute over L of solution, substitute the known molarity of the solution and L of solution to find the moles of solute. To convert from moles of solute to grams of solute, multiply by the molar mass.
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